63rd Kürschák Competition 1963

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1.  mn students all have different heights. They are arranged in m > 1 rows of n > 1. In each row select the shortest student and let A be the height of the tallest such. In each column select the tallest student and let B be the height of the shortest such. Which of the following are possible: A < B, A = B, A > B? If a relation is possible, can it always be realized by a suitable arrangement of the students?
2.  A is an acute angle. Show that (1 + 1/sin A)(1 + 1/cos A) > 5.
3.  A triangle has no angle greater than 90o. Show that the sum of the medians is greater than four times the circumradius.

The original problems are in Hungarian. Many thanks to Péter Dombi for the translation.

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(C) John Scholes
jscholes@kalva.demon.co.uk
19 Apr 2003
Last corrected/updated 19 Apr 2003